Find the zeros of y=x² + 6x-4 by completing the square. A. x = 3± √13 B. x = ±3 C. x = 3+√5 D. x= -3± √13

asked Feb 8, 2023 141k views

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Find the zeros of y=x² + 6x-4 by completing the square.

A. x = 3± √13
B. x = ±3
C. x = 3+√5
D. x= -3± √13

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6 votes

$x^2+6x-4=0\\x^2+6x+9-13=0\\(x+3)^2=13\\x+3=\pm√(13)\\x=-3\pm√(13)$

Tim Walsh answered Feb 13, 2023

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