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What’s the equation of a line that is perpendicular to -x +2y =4 and passes through the point (-2,1)

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Answer:

y = -2x - 3

Explanation:

Given:

Equation of -x +2y =4

Point of (-2,1)

-x + 2y = 4

y = x/2 + 2 or y = 1/2x + 2

Which means the equation's slope is m = 1/2.

The slope of the perpendicular line is negative inverse which is m = -2.

Now we have an equation of y = -2x + a.

Use (-2, 1) to find a:

1 = (-2)(-2) + a

a = -3

y = - 2x - 3

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