Question

Passes through (-6,-1) and is parallel to y=-2/3x+1

Answer 1

`y=-(2)/(3)x -5`

Explanation:

Slope-intercept form:

`y=mx+b\\\\y=(slope)x+(y-intercept)`

• m is the slope
• b is the y-intercept
• x and y are corresponding coordinate points (x,y)

When two lines are parallel, their slopes are the same. Take the slope from the given equation and insert into the new:

`y=-(2)/(3) x+b`

Now find the y-intercept. For this, insert the given coordinate points and the slope into the equation to solve for b:

`(-6_(x),-1_(y))\\\\-1=-(2)/(3) (-6)+b`

Simplify multiplication using the rule
`(a)/(b) *c=(ac)/(b)` :

`-1=-(2(-6))/(3) +b\\\\-1=-(-12)/(3) +b\\\\-1=(12)/(3) +b\\\\-1=4+b`

Use inverse operations to isolate the variable. Subtract 4 from both sides:

`-1-4=4-4+b\\\\-5=b`

The y-intercept is -5. Insert:

`y=-(2)/(3)x -5`

:Done

Answer 2

y=-2/3x-6

Explanation:

y=mx+b

m=-2/3

y-y=m(x-x1)

y-(-1)=-2/3(x-(-6))

y+1=-2/3x-4

-1 -1

y=-2/3x-5