Answer:
2x³ + 3x² - 11x - 6
Step-by-step explanation:
f(x) = (2x + 1)(x - 2)(x + 3)
(2x + 1)(x - 2) = 2x² - 3x - 2
(2x² - 3x - 2)(x + 3) = 2x³ - 3x² - 2x + 6x² - 9x - 6 = 2x³ + 3x² - 11x - 6
2^3+3^2−11−6
(2+1)(−2)(+3)
Distribute
(2+1)(−2)(+3)+1(−2)(+3)
(2x+1)(x−2)(x+3)2(−2)(+3)+1(−2)(+3)+1(−2)(+3)
More Distributing
2(+3)⋅2−4(+3)+1(−2)(+3)
23+62−4(+3)+1(−2)(+3)
Even More Distributing
2^3+6^2−4(+3)+1(−2)(+3)
2^3+6^2−42−12+1(−2)(+3)
Combine like terms
2^3+6^2−4^2−12+1(−2)(+3)
2x^3+2^2−12+1(−2)(+3)
Solution
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