Question

What is the change in internal energy ΔU for a system that releases 241J of heat and does 1.20kJ of work on the surroundings. Answer may be in J or kJ.

Answer 1

`\Delta U=-1,441J`

Step-by-step explanation:

Hello!

In this case, since the first law of thermodynamics explains how the heat added to the system and the work done by the system equals the change in the internal energy of the system, we can write:

`\Delta U=Q-W`

Next, since the system releases 241 J of energy (negative on the previous equation) and does 1.20 kJ (1200 J) of work, the change in the internal energy turns out:

`\Delta U=-241kJ-1,200kJ\\\\\Delta U=-1,441J`

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