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Find the x- and y-intercepts of the line with equation 8x - 4y = -64

2 Answers

3 votes

Answer:

x-intercept:8

y-intercept:16

Explanation:

This is the equation of a straight line. When the line crosses the x-axis that is the x- intercept, the corresponding y-coordinate will be zero. Substituting y = 0 into the equation and solving for x gives the x-intercept.

8x-(4×0)=-64

-8x=-64

x=8 <= the x-intercept.

Similarly, when the line crosses the y-axis the corresponding x- coordinate will be zero. Let x = 0 and solve for y.

(8×0)-4y=-64

-4y=-64

y=16 <= the y-intercept .

User Geoffrey Anderson
by
8.9k points
6 votes

Answer:

x = 1/2

y = -8

Explanation:

Let's solve for x.

8x−4y=−64

Step 1: Add 4y to both sides.

8x−4y+4y=−64+4y

8x=4y−64

Step 2: Divide both sides by 8.

8x/8 = 4y−64 / 8

x= 1/2 y−8

User Dira
by
8.4k points

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