What is the probability that a random arrangement of the letters in the word SEVEN will have both 'E's next to each other?

asked Apr 9, 2023 222k views

7 votes

4.8k points

Please log in or register to add a comment.

7 votes

$|\Omega|=5!=120\\|A|=4\cdot2!\cdot3!=48\\\\P(A)=(48)/(120)=(2)/(5)=40\%$

Zhanger answered Apr 14, 2023

5.3k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.3m questions

6.9m answers