Final answer:
The quadratic inequality that contains the points in the later experiments is -16a + 4b ≥ 48.
Step-by-step explanation:
To find the quadratic inequality that contains the points in the later experiments, we need to consider the maximum height reached by the projectile after 4 seconds.
Let's assume the projectile follows a parabolic path represented by the equation h(t) = -at^2 + bt + c, where h(t) is the height of the projectile at time t, a is the coefficient of the squared term, b is the coefficient of the linear term, and c is a constant.
In this case, the maximum height of 60 feet occurs at t = 4 seconds, so we can substitute these values into the equation to find a quadratic inequality.
We have h(4) = -a(4)^2 + b(4) + c = 60. Considering that the projectile is launched from a height of 12 feet, we can also substitute t = 0 into the equation to find h(0) = -a(0)^2 + b(0) + c = 12.
Combining these equations, we get -a(16) + 4b + c = 60 and c = 12.
Now, we can rewrite the equation as -16a + 4b = 48 and substitute c = 12 into it.
This gives us -16a + 4b = 48. Therefore, the quadratic inequality in a standard form that contains the points in the later experiments is -16a + 4b ≥ 48.