What is 1 times 1? -------------------- 1\cdot \:1 => rewrite using trig equation \left[sin^2\left(x\right)+cos^2\left(x\right)\right]\left[sin^2\left(x\right)+cos^2\left(x\r…

Question

What is 1 times 1?

--------------------


`1\cdot \:1`

=> rewrite using trig equation


`\left[sin^2\left(x\right)+cos^2\left(x\right)\right]\left[sin^2\left(x\right)+cos^2\left(x\right)\right]`


=> simplify


`\left(\sin \:^2\left(x\right)+\cos \:^2\left(x\right)\right)^2`

=> rewrite


`\left(\sin ^2\left(x+0\right)+\cos ^2\left(x+0\right)\right)^2`

=> import java.util.math;

=> apply trig formula


`\sin \:^4\left(x+0\right)+2\sin \:^2\left(x+0\right)\cos \:^2\left(x+0\right)+\cos \:^4\left(x+0\right)`

=> simplify


`\cos ^4\left(x\right)+2\sin ^2\left(x\right)-\sin ^4\left(x\right)`

=> apply trig rule


`y=\cos^(2)\left(x\right)+2\sin^(2)\left(x\right)-\sin^(2)\left(x\right)`

=> plug into a calculator

then the answer is one


math is really easy

math is really easy

Answer 1

i times one is one. no difference