Question

What is the number of sigma and pi bond in butanol?

Answer 1

Sigma Bonds = 14

Pi bonds = 0

Step-by-step explanation:

Butanol:

`\sf CH_(3) -CH_(2)-CH_(2)-CH_(2)-OH`

There is no pi bond in this compound (since there is no double or triply bond)

So,

Pi bond = 0

Now, Coming towards sigma bonds

Sigma bonds = 3 (First carbon with hydrogen) + 2 (Second C with H) + 2 (Third C with H) + 2 (Fourth C with H) + 1 (Bond of O and H) + 4 (Bonds between C and C and C and O)

Sigma Bonds = 14

`\rule[225]{225}{2}`

Hope this helped!

~AnonymousHelper1807