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Segement JK joins J (-2,4) and K (3,-1). Which point is four times as far from K as it is from J?

1 Answer

6 votes

Answer:

P( - 1, 3)

Explanation:

J(- 2, 4), P(x, y), K(3, -1)

KP = 4JP and KP + JP = JK

5JP = JK

JP =
(1)/(5) JK

JK = 5√2

JP = √2

KP = 4√2

2 = (x + 2)² + (y - 4)²

32 = (x - 3)² + (y + 1)²

P( - 1, 3)

Segement JK joins J (-2,4) and K (3,-1). Which point is four times as far from K as-example-1
User Terrace
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