Question

The larger the two numbers is one more than four times the small number. if the sum of the numbers is 106,find the two numbers ​

Answer 1

Smaller no. = 21

Larger no. = 85

Explanation:

Smaller no. = y

Larger no. = 4y + 1

y + (4y + 1) = 106

y + 4y + 1 = 106

5y + 1 = 106

5y = 106 - 1

5y = 105

y = 105/5

y = 21

Smaller no. = y = 21

Larger no. = 4y + 1 = 4×21 + 1 = 84 + 1 = 85