Write an equation in slope-intercept form for the line that passes through (6,- 3) and is parallel to y = -2x + 4.
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Parallel lines are lines with the same slope but different y-intercept.
Slope-intercept form is written as y=mx+b, where m is the slope and b is the y-intercept.
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The given line is y=-2x+4. A line parallel to this would have the same slope, which is -2. To find the y-intercept, plug the point into an equation in point-slope form.
![\displaystyle \text{Point-Slope Form} \rightarrow y-y_(1)=m(x-x_(1))](https://img.qammunity.org/2021/formulas/mathematics/high-school/7k9dk77qmyecqepwezhk1psvttrboqqyzv.png)
m is the slope, and since the slope is the same as the given line, m will be equal to 2.
The line is supposed to pass through a point, which is written as (x, y). In this line, it is supposed to pass (6, -3). x₁ will be the x value of the point, and y₁ will be the y value of the point. That means x₁ is 6 and y₁ is -3.
Substitute the values into the formula:
![y-y_(1)=m(x-x_(1)) \rightarrow y-(-3)=2(x-6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5axa1d5ray6x42h2sb3svy603am351lu7q.png)
When subtracting a negative number from a number or variable, the sign will change, and the number will become positive.
![y-(-3)=y+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/uzhm690wehmo8y3itbr80wveusigqfurgz.png)
Here is the new equation:
![y-3=2(x-6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/zposetjpfl9i9apqotvqg4i2jqks11yz20.png)
Distribute the 2 to everything in the parentheses. It will be 2 times x and 2 times -6. Remember that a positive number multiplied by a negative number is negative.
- Positive(+) times(×) positive(+) = positive(+)
- Positive(-) times(×) negative(-) = negative(-)
- Positive(+) divided(÷) by positive(+) = positive(+)
- Positive(+) divided(÷) by negative(-) = negative(-)
![2 * x=2x\\2 * -6=-12\\\\2(x-6)=2x-12](https://img.qammunity.org/2021/formulas/mathematics/high-school/ookhcp5eptldbjtconszgid9qeuttq2a5t.png)
Rewrite the equation:
![y-3=2x-12](https://img.qammunity.org/2021/formulas/mathematics/high-school/gt97zn88q7i9jqb9ts0ct60zx6qzo7synv.png)
Lastly, you need to move -3 to the other side, as slope-intercept form is written as y=mx+b. You can move it by adding three(+3) to both sides, which is simply doing the opposite of it(-3+3=0).
![\displaystyle y-3+3=2x-12+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/ecrstalqa07cev7e609npk2mlhmqkmhtpv.png)
![y=2x-9](https://img.qammunity.org/2021/formulas/mathematics/high-school/w7zyeov89whnfu6hip2ddff1m58162pycy.png)
The answer to your question is
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