Given:
Initial speed of the motorcycle (u) = 35 m/s
Final speed of the motorcycle (v) = 0 m/s (Complete Stop)
Maximum deceleration of the motorcycle (a) = -1.2 m/s²
Required Equation:

Answer:
By substituting values in the equation, we get:

Time taken by motorcycle to come to a complete stop (t) = 29.167 s