Final answer:
The work done by a 10-newton force acting at a 75-degree angle above the horizontal to move an object 15 meters horizontally would be approximately 38.82 joules. The exact answer is not listed among the provided options.
Step-by-step explanation:
The work done by a force can be calculated using the formula W = F × d × cos(θ), where W is the work, F is the magnitude of the force, d is the distance moved by the object, and θ is the angle the force makes with the direction of motion. In this case, a force of 10 newtons acts at a 75-degree angle to the horizontal, moving the object 15 meters along the horizontal axis.
To find the work done by the force:
- Calculate the horizontal component of the force: Fhorizontal = F × cos(θ) = 10 N × cos(75°).
- Use the work formula with the horizontal component: W = Fhorizontal × d = (10 N × cos(75°)) × 15 m.
- Calculating this gives us the work done by the force.
However, since you're looking for an answer out of the given options, you can see that the correct one is not listed. To explicitly calculate it:
Fhorizontal = 10 N × cos(75°) = 10 × 0.2588 = 2.588 N (approximately)
W = 2.588 N × 15 m = 38.82 J (approximately)
Therefore, the correct answer, if it were listed, would be approximately 38.82 joules.