Question

What volume is occupied by 3.00 moles of nitrogen under a pressure of 202 kPa and a temperature of 323K? R = 8.314 kPa L/mol K INICI​

Answer 1

39.9 L

Step-by-step explanation:

Use PV = nRT to solve this problem.

Substitute the values known.

P is pressure, which is 202 kPa, V is volume, which we do not know, n is moles, which is 3, R is 8.314, and T is temperature, which is 323K.

Set up your equation as follows
`202 kPa V = 3.00mol ((8.314 kPa L )/(mol K) ) 323K`

Solve for V, multiply the right side of the equation and divide by the pressure, 202 kPa.

This results in Volume being 39.9 L