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Given rectangle QUAD, If DU = 5x - 4 and QP = 2x + 7, then find the length of DU.

Given rectangle QUAD, If DU = 5x - 4 and QP = 2x + 7, then find the length of DU.-example-1
User CgodLEY
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1 Answer

5 votes

Answer:

DU = 86

Explanation:

Properties of a rectangle,

- Opposite sides are equal in measure.

- Diagonals of a rectangle are equal.

- Diagonals bisect each other.

In the given rectangle QUAD,

Diagonals AQ and DU bisect each other at P.

AQ = DU

2(QP) = DU [Since, AQ = 2(PQ)]

2(2x + 7) = 5x - 4

4x + 14 = 5x - 4

5x - 4x = 14 + 4

x = 18

Since, DU = 5x - 4

DU = 5(18) - 4

= 90 - 4

= 86

Therefore, measure of DU = 86 units

User Adnauseam
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