Question

When heated, calcium carbonate decomposes according to the equation given below:

CaCO3 --> CaO + CO2
How many liters of CO2 at STP are produced when 0.68 mol of CaCO3 is heated?

15.2 L
30.4 L
0.679 L
68.0 L

Answer 1

15.2L at STP

Step-by-step explanation:

Given reaction expression;

CaCO₃ → CaO + CO₂

Number of moles of CaCO₃ = 0.68mol

Unknown:

Volume of CO₂ produced at STP = ?

Solution:

To solve this problem, we must first find the number of moles CO₂ produced,

1 mole of CaCO₃ will produce 1 mole of CO₂

0.68mole of CaCO₃ will produce 0.68mole of CO₂ at STP

Now;

1 mole of gas occupies a volume of 22.4L at STP;

0.68mole of CO₂ will then occupy 0.68 x 22.4 = 15.2L at STP