Question

A skateboard rolls off a horizontal ledge that is 1.12 m high, and lands

1.48 m from the base of the ledge.
How much time was he in the air?
(Unit = s)

Answer 1

He was 0.4781 s in air.

Step-by-step explanation:

This question is on an object launched horizontally with zero angle and at a height H.

The formula to apply is ;

`T=\sqrt{(2H)/(g) }`

where ;

T=time of flight = ?

H= height of the object was launched = 1.12 m

T= √2*1.12/9.8

T=√0.22857

T= 0.4781 seconds