How do you figure out the square root of z^2+8z+16?

Question

asked Feb 21, 2021 39.5k views

1 Answer

Bastin Robin · Answer 1 · 2021-02-25T19:13:31+0000

Explanation:

Hey there!

Given;

$= \sqrt{ {z}^(2) + 8z + 16}$

Looking through question, we can bring it to perfect square to remove the (√) sqrt.

$\sqrt{( {z)}^(2) + 2.4x + {4}^(2) }$

We made this to bring it in the form of (a+b)^2. As (a+b)^2 = a^2 + 2.a.b + b^2.

Now, our question looks like similar to the formula.

So, We can write it as:

$\sqrt{( {z + 4)}^(2) }$

Now, we can cancel (√) and (^2). And we get

= z + 4

Hope it helps...