Question

A skier is accelerating down a 30.0-degree hill at 3.80 m/s^2.

What is the vertical component of her acceleration? (in m/s^2)

What is the horizontal component of her acceleration? (in m/s^2)
plzzzz help

Answer 1

ax = -3.29[m/s²]

ay = -1.9[m/s²]

Step-by-step explanation:

We must remember that acceleration is a vector and therefore has magnitude and direction.

In this case, it is accelerating downwards, therefore for a greater understanding we will make a diagram of said vector, this diagram is attached.

`a_(x)=-3.8*cos(30) = -3.29 [m/s^(2)]\\ a_(y)=-3.8*sin(30) = -1.9 [m/s^(2)]`