Question

A plane decelerates at a constant rate of 3.9 m/s [W]. If the

plane's initial velocity was 24 m/s [E], how long does it take for the
plane to come to a complete stop?

Answer 1

t = 6.15 [s]

Step-by-step explanation:

To solve this problem we must use the following equation of kinematics.

`v_(f)=v_(o)-a*t`

where:

Vf = final velocity = 0 (the plane comes to stop)

Vo = initial velocity = 24 [m/s]

a = desacceleration = 3.9 [m/s²]

t = time [s]

Note: The negative sign of the acceleration means that the plane is decreasing its velocity.

`0=24-3.9*t\\3.9*t = 24\\t = 6.15[s]`