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Differentiate Sec²x + Tan²x​

User Gramcha
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2 Answers

22 votes
22 votes

Answer:

1+sin(×)²

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cos(×)²

User Barry Pitman
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17 votes
17 votes


~~~(d)/(dx)( \sec^2 x + \tan^2 x)\\\\\\=(d)/(dx)( 1+ \tan^2 x + \tan^2 x)~~~~~~~~~~~~;[\sec^2 x - \tan^2 x =1]\\\\\\=(d)/(dx)(1+2\tan^2 x)\\\\\\=0 +2 (d)/(dx) \tan^2 x\\\\\\=2 \cdot 2 \tan x (d)/(dx) \tan x\\\\\\=4 \tan x \cdot \sec^2 x\\

User David Bradshaw
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