Question

The ratio of effusion ratios between He(g) and SF6(g) is

Answer 1

rate He = 6 x rate SF₆

Further explanation

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or

the effusion rates of two gases = the square root of the inverse of their molar masses:

`\rm (r_1)/(r_2)=\sqrt{(M_2)/(M_1) }`

or

`\rm M_1* r_1^2=M_2* r_2^2`

M He = 4 g/mol

M SF₆ = 146 g/mol

`\tt (r_(He))/(r_(SF_6))=\sqrt{(146)/(4) }=6.04\approx 6\\\\r_(He)=6~r_(SF_6)`