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Write the equation of a line that is perpendicular to y = 1/5 x + 12 passes through the point (- 4, 1)

Write the equation of a line that is perpendicular to y = 1/5 x + 12 passes through-example-1

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1 vote

Answer:

y = -5x - 19

Step-by-step explanation:

The equation of the line is given as:

y =
(1)/(5)x + 12

Points = (-4, 1)

Now,

A line perpendicular to this given line will have slope which is a negative inverse of the given one.

Any straight line will have the equation;

y = mx + c

y and x are the coordinates

m is the slope

c is the y-intercept;

y =
(1)/(5)x + 12 , slope of a line perpendicular is -5;

Let us find the y-intercept c, of the new line;

1 = -5(-4) + c

1 = 20 + c

c = -19

Now, the equation of the line is;

y = -5x - 19

User Hayden Chambers
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