187k views
1 vote
A set of 4 consecutive odd integers has a sum of 216. What are the integers?​

User Mikael M
by
7.4k points

1 Answer

3 votes

Answer:

Hope this helps!!

Explanation:

So the four consecutive odd integers are: 51 , 53 , 55 and 57 .

If the first integer is n, then the other three are n+2,n+4 and n+6

and we have:

216=n+(n+2)+(n+4)+(n+6)=4n+12

Subtract 12 from both ends and transpose to get:

4n=204

Divide both sides by 4

to get:

n=51

So the four consecutive odd integers are:

51,53, 55 and 57.

User Crockeea
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories