Question

"eight times the difference of a number and three is sixty-four"?

Answer 1

the number would be 11

Explanation:

8 · x - 3 = 64

________ _ (divide both sides by 8)

8 8

x - 3 = 8

+ 3 + 3

x = 11

(check:

11 - 3 = 8

8 x 8 = 64 )

Answer 2

Hi student, let me help you out!

................................................................................................................................

`\bold{Let:}`
`\star`

`\mathsf{s\:be\:the\:number}`

The little phrase (eight times) tells us to multiply s times 8:
`\mathsf{8s}`.

The phrase (the difference of) tells us to subtract 3 minus s:
`\mathsf{s-3}`.

Now, the problem also tells us to multiply 8 times 3-s:
`\mathsf{8(s-3)}`.

Notice I put parentheses around 3-s. This tells us to multiply 8 times both terms - 3 and -s.
`\star`

Finally, this expression is 64. All of our hard work results in the following equation: ✨
`\bigstar\underline{\boxed{\mathrm{8(s-3)=64}}}`
`\star`

Hope this helped you out, ask in comments if any queries arise.

Best Regards!
`\star`

`\star\bigstar\underline{\underline{\overline{\overline{\bold{Reach\:far.\:Aim\:high.\:Dream\:big.}}}}}\bigstar\star`