Question

Determine the solution of the linear equation x^2-2x=8

Answer 1

Work shown below!

Explanation:

`x^(2) -2x=8`

Subtract 8 from both sides;

`x^(2) -2x-8=0\\(x+2)(x-4)=0`

x + 2 = 0

Subtract 2 from both sides;

x = -2

x - 4 = 0

Add 4 to both sides;

x = 4

Answer 2

x=-2 and 4

Explanation:

First of all, this is not a linear equation, but a quadratic equation which has two answers (or otherwise known as roots, solutions, or zeroes)

We can start by subtracting the 8 on both sides

x^2-2x-8=0

We can factor this, so we take two factors that multiply to -8 and two factors that add to -2

(x-4)(x+2)

Set those equal to zero x-4=0 and x+2=0

So x=-2 and 4