Question

What is the general equation of the line that passes through (4, -1) and (-2, 3)?

Answer 1

y=-2/3x+7

Explanation:

(4, -1) and (-2, 3)

m=y²-y¹/x²-x¹

m=3-(-1)/(-2)-4

m=4/-6

m=-2/3

y-y=m(x-x1)

y-(-1)=-2/3(x-4)

y+1=-2/3x+8

-1 -1

y=-2/3x+7