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What is the value of k that makes the equation (4x^2y^2+5xy+k)+(kx^2y^2-2xy-6)=7x^2+kxy-3

1 Answer

2 votes

Answer:

k=7x^(2)-4x^(2)y^(2)-3xy+3

x^(2)y^(2)-xy

pretend the underline is like the line for a fraction/ division

Explanation:

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