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Passing through (9,-9) and perpendicular ti the line whose equation is x -3y-4 =0

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Answer:

3x +y -18 = 0

Explanation:

The equation of the perpendicular line can be formed from the given equation by swapping the x- and y-coefficients, and negating one of them. The constant in the new equation will be the constant necessary to make the line pass through the given point.

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swapped coefficients

3x +y +c = 0 . . . . . now both coefficients are positive

new constant

We want c such that the equation is satisfied at the point (x, y) = (9, -9):

3(9) +(-9) +c = 0

27 -9 +c = 0

c = -18

equation of perpendicular line

The equation of the desired line is ...

3x +y -18 = 0

Passing through (9,-9) and perpendicular ti the line whose equation is x -3y-4 =0-example-1
User F Perroch
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