Question

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#51 & 52. Write the standard equation of the circle. ​

Answer 1

#51

Centre (3,1)

Radius=2

Equation

• (x-h)²+(y-k)²+r²
• (x-3)²+(y-1)²=2²
• (x-3)²+(y-1)²=4

#52

centre(-3,2)

radius=2

Equation

• (x+3)²+(y-2)²=4

Answer 2

Answers:

Question 51.
`\boldsymbol{(x-3)^2 + (y-1)^2 = 4}`

Question 52.
`\boldsymbol{(x+3)^2 + (y-2)^2 = 4}`

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Step-by-step explanation:

The template of any circle is

`(x-h)^2 + (y-k)^2 = r^2`

with (h,k) being the center and r as the radius

For question 51, the center is (3, 1) and the radius is 2. So,

`(x-h)^2 + (y-k)^2 = r^2\\\\(x-3)^2 + (y-1)^2 = 2^2\\\\(x-3)^2 + (y-1)^2 = 4`

Question 52 will have similar steps. This time the center is (-3, 2) and the radius is 2.