Question

8. An airplane is flying at 200 m/s when it touches the ground at the airport. It has a constant negative acceleration, and slows

down to a speed of 4 m/s after it traveled a length of 4,000 meters. What was the acceleration?

Answer 1

Step-by-step explanation:

Given

Initial velocity u = 200m/s

Final velocity = 4m/s

Distance S = 4000m

Required

Acceleration

Substitute the given parameters into the formula

v² = u²+2as

4² = 200²+2a(4000)

16 = 40000+8000a

8000a = 16-40000

8000a = -39,984

a = - 39,984/8000

a = -4.998m/s²

Hence the acceleration is -4.998m/s²