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Solve |y + 2| > 6
pls help

User Muhasturk
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1 Answer

4 votes

Answer:

Explanation:

Definition of an absolute value is:


|a|=\left \{ {{a, if a\geq 0} \atop {-a, if a<0}} \right.

1). Assume that (y + 2) ≥ 0, then

y + 2 > 6 ⇒ y > 4

2). Now, if (y + 2) < 0, then

- (y + 2) > 6 ⇔ - y - 2 > 6 ⇒ y < - 8

y ∈ ( - ∞ , - 8) ∪ (4 , ∞ )

Solve |y + 2| > 6 pls help-example-1