Answer:
The distance apart of the two planes is either 100.45 km or 64.40 km
Explanation:
The given parameters are;
The angle of elevation of the plane from the two radar stations are; 20° and 59°
The altitude of the plane = 30 km
The horizontal distance from each of the radar stations from the plane is given as follows;
![tan(\theta) = (Altitude \ of \ the \ plane)/(The \ horizontal \ distance \ of \ radar \ station \ from \ the \ plane)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qx66ijfxrx43pg1brqcir8jl20rfiyp4og.png)
Therefore, we have;
For each of the given radar stations, and their elevations, we have;
![The \ horizontal \ distance \ of \ the \ 1st \ radar \ station \ from \ the \ plane = (30 \ km)/(tan(20^(\circ)))](https://img.qammunity.org/2021/formulas/mathematics/high-school/pqrlxnjtq6k4z0i9iq6qjy4o11mn47mfr7.png)
![The \ horizontal \ distance \ of \ the \ 2nd \ radar \ station \ from \ the \ plane = (30 \ km)/(tan(59^(\circ)))](https://img.qammunity.org/2021/formulas/mathematics/high-school/bg5slhtnnb1f89cm5c4skgdsvx9bw3w6cc.png)
The distance between the two radar stations, d = The sum of their horizontal distances from the plane
Therefore;
![d = (30 \ km)/(tan(20^(\circ))) + (30 \ km)/(tan(59^(\circ))) \approx 100.45 \ km](https://img.qammunity.org/2021/formulas/mathematics/high-school/ciab9ob2qnhjwdbe0ddlf3b09hesyeoq4m.png)
However, when the radar stations are on the same side, we have;
The distance between the two radar stations, dₓ = The difference of their horizontal distances from the plane
![d_x = (30 \ km)/(tan(20^(\circ))) - (30 \ km)/(tan(59^(\circ))) \approx 64.40 \ km](https://img.qammunity.org/2021/formulas/mathematics/high-school/j0o3fu77i5zozgx90zl8y27es9b1gt3xdo.png)
The distance apart of the two planes is either 100.45 km or 64.40 km