Question

How much tension must a rope withstand if it is used to accelerate a 960 kg car horizontally along a frictionless track at 1.20 m/s²?

Answer 1

T=ma
T=960*1.2
T=1152 N

Answer 2

The tension of the rope is 1152 N

Step-by-step explanation:

Force

Newton's second law states that the acceleration of an object is directly proportional to the net force and inversely related to its mass.

The law can be written as:

F = m.a

The rope must apply a force F to accelerate the car of m=960 Kg at
`a=1.2~ m/s^2`. Given the track is frictionless, all the force applied produces acceleration, thus:

`F = 960~Kg\cdot 1.2~ m/s^2`

F = 1152 N

The tension of the rope is 1152 N