Question

One number is 6 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 404 ​, find the numbers

Answer 1

1st number: 38

2nd number: 228

3rd number: 138

Explanation:

Lets call the first number x

The second number is 6x

The third number is x+100

x+6x+x+100=404

8x+100=404

8x=304

x=38

The first number is 38

The second number is 6(38), which is 228

The third number is 38+100, which is 138

38+138+220 = 404