(2n) (2m + 1) = [? ]mn + [ In = = 2([]mn + [ ]n) = even

Tadas T asked Oct 27, 2023

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27 votes

(2n) (2m + 1) = [? ]mn + [ In
=
= 2([]mn + [ ]n)
= even

Tadas T asked Oct 27, 2023

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13 votes

Explanation:

(2n)(2m + 1) = 4nm + 2n = 2(2mn + 1n) = even

Oguz Bilgic answered Nov 2, 2023

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