Answer:
Explanation:
Refer to attached
Given
To find
Solution
- Let the area of ABC be A, then
- A = 1/2bh, where b= AC is the base and h is the height of the triangle
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The triangle DCF can be divided into DEC and DEF as per picture and the area of them is:
Area of ΔDEF
Area of ΔDEC
Since D and E are midpoints of AB and BC:
- And h1 = 1/2h,
- h2 = 1/2h1 = 1/2*1/2h = 1/4h
So the area of ΔDCF is:
- 1/2(1/2bh1) + 1/2(1/2bh2) =
- 1/2(1/2b*1/2h) + 1/2(1/2b*1/4h) =
- 1/8bh + 1/16bh =
- 3/16bh
Since the area of ABC is A = 1/2bh we have:
- 3/8*1/2bh = 3/8A and
- 3/8A = 63
Solving for A: