208k views
1 vote
HELP ME

please help me :,(

algebra
what are the roots, and y intercept of g (x)?

f (x)=(x-2)(x+3)(x-4)(x+1)
g (x)= -f (x+3)​

User Bumperbox
by
7.1k points

1 Answer

6 votes

Answers:

Roots of g(x) are: -1, -6, 1, -4

Y intercept of g(x) is: 24

==============================================

Step-by-step explanation:

Part 1) Finding the roots of g(x)

To do this, we need the roots of f(x). Plug in f(x) = 0 and solve for x using the zero product property.

f(x) = (x-2)(x+3)(x-4)(x+1)

0 = (x-2)(x+3)(x-4)(x+1)

(x-2)(x+3)(x-4)(x+1) = 0

x-2 = 0 or x+3 = 0 or x-4 = 0 or x+1 = 0

x = 2 or x = -3 or x = 4 or x = -1

Those four x values are the roots of f(x). Plugging any of those values into f(x) leads to f(x) = 0.

Now onto g(x). We see that g(x) = -f(x+3). The x+3 indicates the xy axis has been shifted by 3 units to the right. This gives the illusion the f(x) curve is shifted 3 units to the left. This will move each root 3 units to the left as well.

  • The root x = 2 on f(x) moves to x = -1 on g(x). We subtract 3 from the first x value to get the second x value.
  • The root x = -3 on f(x) moves to x = -6 on g(x). Same idea as above.
  • The root x = 4 on f(x) moves to x = 1 on g(x).
  • The root x = -1 on f(x) moves to x = -4 on g(x).

The four roots of g(x) are: -1, -6, 1, -4

------------------------------------------------

Part 2) The y intercept of g(x)

Let's plug x = 0 into g(x) to see what happens

g(x) = -f(x+3)

g(0) = -f(0+3) ... replace every x with 0

g(0) = -f(3)

We don't know f(3) yet, but we can plug x = 3 into f(x) to find out

f(x) = (x-2)(x+3)(x-4)(x+1)

f(3) = (3-2)(3+3)(3-4)(3+1)

f(3) = (1)(6)(-1)(4)

f(3) = -24

Therefore,

g(0) = -f(3)

g(0) = -(-24)

g(0) = 24

The y intercept of g(x) is 24.

User Dencey
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.