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Determine the point that is 3/4 the distance from the endpoint (−6,−16)(−6,−16) of the segment with endpoints (34,2)(34,2) and (−6,−16)(−6,−16).

what, pls explain cus there is other questions similar to this​

1 Answer

5 votes

Answer:

The location of the point that is 3/4 the distance from
A(x,y) is
C(x,y) = (24, -2.5).

Explanation:

Let
A(x,y) = (-6,-16) and
B(x,y) = (34,2) the endpoints of the segment, we can determine the location of the point that is 3/4 the distance from
A(x,y) by the following vector equation:


C(x,y) = A(x,y) + (3)/(4)\cdot (B(x,y)-A(x,y)) (1)

If we know that
A(x,y) = (-6,-16) and
B(x,y) = (34,2), the location of
C(x,y) is:


C(x,y) = (-6,-16)+(3)/(4)\cdot [(34,2)-(-6,-16)]


C(x,y) = (-6,-16)+(3)/(4)\cdot (40,18)


C(x,y) = (24, -2.5)

The location of the point that is 3/4 the distance from
A(x,y) is
C(x,y) = (24, -2.5).

User Amir Beygi
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