Let me try:
Normal force= 169.74N
Coefficient of kinetic friction= 0.577
Step-by-step explanation
a. For a given inclined plane, normal friction is equal to the force perpendicular to the plane which is equal to
mgcos theta = 20×9.8× cos30 = 169.74N
b. The coefficient of kinetic friction for an inclined plane is given as
tan theta =tan 30 = 0.577