Question

Find the equation of the line that is perpendicular to the given line and passes through the given point.

y=-x
y=---9; (13,0)
2
The equation is y =
(please help me)

Answer 1

y = 2x - 26

Explanation:

y =
`-(1)/(2)` x - 9 ⇒ slope m =
`-(1)/(2)` ⇒ slope of ⊥ line m = 2

(13, 0)

y - 0 = 2(x - 13)

y = 2x - 26