Question

Write an equation of a line that passes through (-6,4) and is PERPENDICULAR to y=3x-11

Answer 1

y = -1/3x + 2

General Formulas and Concepts:

Pre-Algebra

• Order of Operations: BPEMDAS
• Equality Properties

Algebra I

Perpendicular lines have the negative reciprocal slope of the original.

Slope-Intercept Form: y = mx + b

• m - slope

• b - y-intercept

Explanation:

Step 1: Define

y = 3x - 11

Point (-6, 4)

Step 2: Find slope m

Negative Reciprocal of 3 = -1/3

Step 3: Define

y = -1/3x + b

Step 4: Find y-intercept b

1. Substitute in point: 4 = -1/3(-6) + b
2. Multiply: 4 = 2 + b
3. Subtract 2 on both sides: 2 = b
4. Rewrite: b = 2

Step 5: Write perpendicular linear equation

y = -1/3x + 2