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Solve the system of equations 2x-y= 13x and -3x+2y=-18 by combining the equations.

User Vijay V
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1 Answer

6 votes

Answer:

x = 18/25, y = -198/25

Explanation:

Given the system of equations:

2x – y = 13x

-3x + 2y= -18

You can combine these two equations effectively by multiplying the first equation by 2, and adding because -2y and 2y will cancel out when added. So you will be left with only x terms

( 2x - y = 13x ) × 2

+ -3x + 2y = -18

________________

2(2x) - 3x + 2(-y) + 2y = 2(13x) - 18

4x - 3x - 2y + 2y = 26x - 18

x + 0 = 26x - 18

x = 26x - 18

________________

[Then use the properties of equality to simplify the expressions in the equation to derive the value of x]

x - x = 26x - 18 - x (subtraction property of equality)

0 = 25x - 18

0 + 18 = 25x - 18 + 18 (addition property of equality)

18 = 25x

18 / 25 = 25x / 25 (division property of equality)

18 / 25 = x

x = 18 / 25 (symmetric property of equality)

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Now with the value of x, we can find the value of y by substituting the value of x into the variables of the top equation {2x – y = 13x} because this involves the simpliest steps.

Given x = 18 / 25.

2x – y = 13x → 2x – y + y = 13x + y → 2x = 13x + y → 2x – 13x = 13x + y – 13x → -11x = y → y = -11x.

Now that we know y = -11x, y = -11(18/25) which is - (11 × 18) / 25 = -198/25

User ElefEnt
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