Question

6x^2 – 13x + 6 = 2x^2 solve using quadratic formula

Answer 1

`x=(13\pm√(73) )/(8)`

General Formulas and Concepts:

Pre-Algebra

• Order of Operations: BPEMDAS
• Equality Properties

Algebra I

• Standard Form: ax² + bx + c = 0
• Quadratic Formula:
  `x=(-b\pm√(b^2-4ac) )/(2a)`

Explanation:

Step 1: Define equation

6x² - 13x + 6 = 2x²

Step 2: Rewrite in Standard Form

1. Subtract 2x² on both sides: 4x² - 13x + 6 = 0

Step 3: Define

a = 4

b = -13

c = 6

Step 4: Solve for x/roots

1. Substitute:
   `x=(13\pm√((-13)^2-4(4)(6)) )/(2(4))`
2. Exponent:
   `x=(13\pm√(169-4(4)(6)) )/(2(4))`
3. Multiply:
   `x=(13\pm√(169-96) )/(8)`
4. Subtract:
   `x=(13\pm√(73) )/(8)`

And we have our final answer!