Question

A sled is pulled at a constant velocity across a horizontal snow surface. If a force of 100 N is being applied to the sled rope parallel to the ground, what is the force of friction between the sled and the snow?

Answer 1

60.18 N

Step-by-step explanation:

Given that:

The force applied on the sled = 100 N

Suppose, the angle between the sled rope and the ground = 53°

The horizontal force which acts in the horizontal direction can be expressed as:

`F_x = F \ cos \theta`

`F_x = 100 \ cos (53)`

`F_x = 60.18 \ N`

But if the angle between the sled rope is parallel to the ground. Then, we use an angle on a straight line which is = 180°

`F_x = F \ cos \theta`

`F_x = 100 \ cos (180)`

= 100 × -1

= -100 N