Question

A ball projected horizontally from 180meter tall building lands 450 meter away from the foot of the building find velocity of the ball after leafs the building find velocity of the ball after it leafs the building​

Answer 1

74.28 m/s

Step-by-step explanation:

In this case, it is a zero launch angle in that the object is launched horizontally at a height H.

The formula to apply is:

`R=v_o*\sqrt{(2H)/(g) }`

where

R= range, 450 m

H= height of building ,180 m

g= 9.81

vo= ? initial velocity

Applying the values to the equation;

`450 = v_o*\sqrt{(2*180)/(9.81) } \\\\450=v_o*√(36.70) \\\\450=v_o*6.06\\\\450/6.06 = v_o\\\\74.28 m/s=v_o`