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Find to 3 decimal places the value of t for the distribution for the following.

Area in the left tail 0.005 and n= 25.

Find to 3 decimal places the value of t for the distribution for the following. Area-example-1
User Lucask
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6 votes

Answer:

-2.797

Step-by-sep explanation:

The area in the left tail is the level of significance =
\alpha = 0.005

n = 25

Since sample size, n, = 25,

Degree of freedom = n - 1 = 25 - 1 = 24

The value of t for the t distribution, that is the t critical value, would be:


-t\binom{n - 1}{\alpha} = -t\binom{9}{0.005}

The t critical value can be gotten from the t-table at the intersection of the row representing 24 degrees of freedom and the
t_(0.005) column. This would give us -2.797

The t critical value of the left tail would be critical value is -2.797.

User Variable
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