Question

The charge of a capacitor is 1500μC. Determine the potential difference between the plates if their capacitance is 5μF.

Answer 1

The potential difference between the plates of the capacitor is 300V

Step-by-step explanation:

Given;

capacitance of the capacitor, C = 5μF = 5 x 10⁻⁶ F

charge of the capacitor, Q = 1500μC = 1500 x 10⁻⁶ C

The potential difference between the plates of the capacitor is given by;

V = Q / C

Where;

V is the potential difference between the plates

Q is the charge of the capacitor

C is the capacitance

`V = (Q)/(C) \\\\V = (1500*10^(-6))/(5*10^(-6)) \\\\V = 300 \ volts`

Therefore, the potential difference between the plates of the capacitor is 300V